Brillant, isn’t it? 
Category Archives: Uncategorized
Difference between Upsell & Cross-sell
November 21, 2011 – 7:16 am
In marketing sense,
Upsell refers to selling a similar and expensive product/service.
For example: You walk in to a mobile phone shop wanting to buy a basic phone. However, the salesman is trying to sell you the latest model of Apple iPhone. In this context, we say that the salesman is involved in upselling because an iPhone is a phone and it is more expensive than a mobile phone.
Cross-sell refers to selling a completely different product/service.
For example: You walk in to a mobile phone shop wanting to buy a basic phone. However, the salesman suggests that you should upgrade your mobile plan to enjoy free data access. In this context, the salesman is involved in cross-selling because a mobile plan is completely different from a mobile phone.
The story of 3 monsters
November 8, 2011 – 8:41 pm
Extracted from: http://www.wretch.cc/blog/cwwany/26692785
Online Taiwan Hokkien Radio Streaming
October 11, 2011 – 3:28 pm
Nice! From Happy Radio 96.7 FM Taiwan.
Online streaming @ http://www.streamingthe.net/Happy-Radio-96.7-FM-Taiwan/p/20973&player=1&iconplayer=13
You may need to refresh the site for the player to load.
Enjoy 
[Math] Differentiate Natural Logarithm
October 3, 2011 – 12:45 am
Q1: y = ln(2x)
d/dx [(ln(2x)] = 1/2x . 2
= 1/x
Q2: y = ln(x)^2
d/dx [ln(x)^2] = 1/x^2 . 2x
= 2/x
Alternatively, ln(x)^2 = 2 . ln(x)
d/dx [2 . ln(x)] = 1/x . 2
= 2/x
Q3: y = ln(4x^2)
d/dx [ln(4x^2)] = 1/4x^2 . 8x
= 2/x
APA Citiation Style 6th Edition
September 28, 2011 – 11:20 pm
A very good website that I found, guiding me through American Psychological Association (APA) style in citation. The current edition of APA is 6th.
The website link :: http://rdc.libguides.com/apa
A must-bookmarked site if you are studying in the University!
[Math] Expanding (a^4 – a^4)
September 21, 2011 – 9:07 pm
a4 – b4 = (a2 + b2)(a2 – b2)
Since (a2 – b2) = (a + b)(a – b)
a4 – b4 = (a2 + b2)(a + b)(a – b)
[Math] Finding the three terms in Geometric Progression
September 20, 2011 – 8:53 pm
Q: Three consecutive terms of a G.P. have a sum of 28 and a product of 512. Find the three terms.
Solution:
Let the three numbers in G.P. be (a/r), a, ar
(a/r) * a * ar = 512
a3 = 512
a = 8
(a/r) + a + ar = 28
sub 8 into a, since a = 8
(8/r) + 8 + 8r = 28
8(r2 + r + 1) = 28r
r2 + r + 1 = 3.5r
r2 – 2.4r + 1 = 0
Using roots of quadratic equations formula,
r = (1/2) or r = 2
With a = 12, d = 1/2 or 2
First term: 8 * 2 = 16
Second term: 8
Third term: 8 * (1/2) = 4
OR
First term: 8 / 2 = 4
Second term: 8
Third term: 8 * 2 = 16
[Math] Finding the three terms in Arithmetic Progression
September 18, 2011 – 12:50 pm
Q: Three consecutive terms of an A.P. have a sum of 36 and a product of 1428. Find the three terms.
Solution:
Let the three numbers in A.P. be (a-d), a, (a+d)
(a-d)+a+(a+d) = 36
3a = 36
a = 12
(a-d)(a)(a+d) = 1428
a(a2-d2) = 1428
12(122-d2) = 1428
(144-d2) = 119
d2 = 25
d = sqrt(25)
= +5 or -5
With a = 12, d = +5 or -5
First term: 12-5 = 7
Second term: 12
Third term: 12+5 = 17
OR
First term: 12+5 = 17
Second term: 12
Third term: 12-5 = 7
Answer: 7, 12, 17
